Optimal. Leaf size=192 \[ \frac{2 d^2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac{4 d (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^3}+\frac{2 (d+e x)^{7/2} \left (a+b \log \left (c x^n\right )\right )}{7 e^3}-\frac{32 b d^3 n \sqrt{d+e x}}{105 e^3}-\frac{32 b d^2 n (d+e x)^{3/2}}{315 e^3}+\frac{32 b d^{7/2} n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )}{105 e^3}+\frac{36 b d n (d+e x)^{5/2}}{175 e^3}-\frac{4 b n (d+e x)^{7/2}}{49 e^3} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.176065, antiderivative size = 192, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.261, Rules used = {43, 2350, 12, 897, 1261, 208} \[ \frac{2 d^2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac{4 d (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^3}+\frac{2 (d+e x)^{7/2} \left (a+b \log \left (c x^n\right )\right )}{7 e^3}-\frac{32 b d^3 n \sqrt{d+e x}}{105 e^3}-\frac{32 b d^2 n (d+e x)^{3/2}}{315 e^3}+\frac{32 b d^{7/2} n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )}{105 e^3}+\frac{36 b d n (d+e x)^{5/2}}{175 e^3}-\frac{4 b n (d+e x)^{7/2}}{49 e^3} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 43
Rule 2350
Rule 12
Rule 897
Rule 1261
Rule 208
Rubi steps
\begin{align*} \int x^2 \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right ) \, dx &=\frac{2 d^2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac{4 d (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^3}+\frac{2 (d+e x)^{7/2} \left (a+b \log \left (c x^n\right )\right )}{7 e^3}-(b n) \int \frac{2 (d+e x)^{3/2} \left (8 d^2-12 d e x+15 e^2 x^2\right )}{105 e^3 x} \, dx\\ &=\frac{2 d^2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac{4 d (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^3}+\frac{2 (d+e x)^{7/2} \left (a+b \log \left (c x^n\right )\right )}{7 e^3}-\frac{(2 b n) \int \frac{(d+e x)^{3/2} \left (8 d^2-12 d e x+15 e^2 x^2\right )}{x} \, dx}{105 e^3}\\ &=\frac{2 d^2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac{4 d (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^3}+\frac{2 (d+e x)^{7/2} \left (a+b \log \left (c x^n\right )\right )}{7 e^3}-\frac{(4 b n) \operatorname{Subst}\left (\int \frac{x^4 \left (35 d^2-42 d x^2+15 x^4\right )}{-\frac{d}{e}+\frac{x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{105 e^4}\\ &=\frac{2 d^2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac{4 d (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^3}+\frac{2 (d+e x)^{7/2} \left (a+b \log \left (c x^n\right )\right )}{7 e^3}-\frac{(4 b n) \operatorname{Subst}\left (\int \left (8 d^3 e+8 d^2 e x^2-27 d e x^4+15 e x^6+\frac{8 d^4}{-\frac{d}{e}+\frac{x^2}{e}}\right ) \, dx,x,\sqrt{d+e x}\right )}{105 e^4}\\ &=-\frac{32 b d^3 n \sqrt{d+e x}}{105 e^3}-\frac{32 b d^2 n (d+e x)^{3/2}}{315 e^3}+\frac{36 b d n (d+e x)^{5/2}}{175 e^3}-\frac{4 b n (d+e x)^{7/2}}{49 e^3}+\frac{2 d^2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac{4 d (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^3}+\frac{2 (d+e x)^{7/2} \left (a+b \log \left (c x^n\right )\right )}{7 e^3}-\frac{\left (32 b d^4 n\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{d}{e}+\frac{x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{105 e^4}\\ &=-\frac{32 b d^3 n \sqrt{d+e x}}{105 e^3}-\frac{32 b d^2 n (d+e x)^{3/2}}{315 e^3}+\frac{36 b d n (d+e x)^{5/2}}{175 e^3}-\frac{4 b n (d+e x)^{7/2}}{49 e^3}+\frac{32 b d^{7/2} n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )}{105 e^3}+\frac{2 d^2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac{4 d (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^3}+\frac{2 (d+e x)^{7/2} \left (a+b \log \left (c x^n\right )\right )}{7 e^3}\\ \end{align*}
Mathematica [A] time = 0.195985, size = 151, normalized size = 0.79 \[ \frac{2 \sqrt{d+e x} \left (105 a \left (-4 d^2 e x+8 d^3+3 d e^2 x^2+15 e^3 x^3\right )+105 b \left (-4 d^2 e x+8 d^3+3 d e^2 x^2+15 e^3 x^3\right ) \log \left (c x^n\right )-2 b n \left (-179 d^2 e x+778 d^3+108 d e^2 x^2+225 e^3 x^3\right )\right )+3360 b d^{7/2} n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )}{11025 e^3} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.593, size = 0, normalized size = 0. \begin{align*} \int{x}^{2} \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) \sqrt{ex+d}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A] time = 1.47922, size = 990, normalized size = 5.16 \begin{align*} \left [\frac{2 \,{\left (840 \, b d^{\frac{7}{2}} n \log \left (\frac{e x + 2 \, \sqrt{e x + d} \sqrt{d} + 2 \, d}{x}\right ) -{\left (1556 \, b d^{3} n - 840 \, a d^{3} + 225 \,{\left (2 \, b e^{3} n - 7 \, a e^{3}\right )} x^{3} + 9 \,{\left (24 \, b d e^{2} n - 35 \, a d e^{2}\right )} x^{2} - 2 \,{\left (179 \, b d^{2} e n - 210 \, a d^{2} e\right )} x - 105 \,{\left (15 \, b e^{3} x^{3} + 3 \, b d e^{2} x^{2} - 4 \, b d^{2} e x + 8 \, b d^{3}\right )} \log \left (c\right ) - 105 \,{\left (15 \, b e^{3} n x^{3} + 3 \, b d e^{2} n x^{2} - 4 \, b d^{2} e n x + 8 \, b d^{3} n\right )} \log \left (x\right )\right )} \sqrt{e x + d}\right )}}{11025 \, e^{3}}, -\frac{2 \,{\left (1680 \, b \sqrt{-d} d^{3} n \arctan \left (\frac{\sqrt{e x + d} \sqrt{-d}}{d}\right ) +{\left (1556 \, b d^{3} n - 840 \, a d^{3} + 225 \,{\left (2 \, b e^{3} n - 7 \, a e^{3}\right )} x^{3} + 9 \,{\left (24 \, b d e^{2} n - 35 \, a d e^{2}\right )} x^{2} - 2 \,{\left (179 \, b d^{2} e n - 210 \, a d^{2} e\right )} x - 105 \,{\left (15 \, b e^{3} x^{3} + 3 \, b d e^{2} x^{2} - 4 \, b d^{2} e x + 8 \, b d^{3}\right )} \log \left (c\right ) - 105 \,{\left (15 \, b e^{3} n x^{3} + 3 \, b d e^{2} n x^{2} - 4 \, b d^{2} e n x + 8 \, b d^{3} n\right )} \log \left (x\right )\right )} \sqrt{e x + d}\right )}}{11025 \, e^{3}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [A] time = 12.9761, size = 364, normalized size = 1.9 \begin{align*} \frac{2 \left (\frac{a d^{2} \left (d + e x\right )^{\frac{3}{2}}}{3} - \frac{2 a d \left (d + e x\right )^{\frac{5}{2}}}{5} + \frac{a \left (d + e x\right )^{\frac{7}{2}}}{7} + b d^{2} \left (\frac{\left (d + e x\right )^{\frac{3}{2}} \log{\left (c \left (- \frac{d}{e} + \frac{d + e x}{e}\right )^{n} \right )}}{3} - \frac{2 n \left (\frac{d^{2} e \operatorname{atan}{\left (\frac{\sqrt{d + e x}}{\sqrt{- d}} \right )}}{\sqrt{- d}} + d e \sqrt{d + e x} + \frac{e \left (d + e x\right )^{\frac{3}{2}}}{3}\right )}{3 e}\right ) - 2 b d \left (\frac{\left (d + e x\right )^{\frac{5}{2}} \log{\left (c \left (- \frac{d}{e} + \frac{d + e x}{e}\right )^{n} \right )}}{5} - \frac{2 n \left (\frac{d^{3} e \operatorname{atan}{\left (\frac{\sqrt{d + e x}}{\sqrt{- d}} \right )}}{\sqrt{- d}} + d^{2} e \sqrt{d + e x} + \frac{d e \left (d + e x\right )^{\frac{3}{2}}}{3} + \frac{e \left (d + e x\right )^{\frac{5}{2}}}{5}\right )}{5 e}\right ) + b \left (\frac{\left (d + e x\right )^{\frac{7}{2}} \log{\left (c \left (- \frac{d}{e} + \frac{d + e x}{e}\right )^{n} \right )}}{7} - \frac{2 n \left (\frac{d^{4} e \operatorname{atan}{\left (\frac{\sqrt{d + e x}}{\sqrt{- d}} \right )}}{\sqrt{- d}} + d^{3} e \sqrt{d + e x} + \frac{d^{2} e \left (d + e x\right )^{\frac{3}{2}}}{3} + \frac{d e \left (d + e x\right )^{\frac{5}{2}}}{5} + \frac{e \left (d + e x\right )^{\frac{7}{2}}}{7}\right )}{7 e}\right )\right )}{e^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{e x + d}{\left (b \log \left (c x^{n}\right ) + a\right )} x^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]